3.568 \(\int x^3 (a+b \log (c (d+e x^{2/3})))^p \, dx\)

Optimal. Leaf size=557 \[ \frac {2^{-p-2} 3^{-p} e^{-\frac {6 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {6 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^6 e^6}-\frac {3 d 5^{-p} e^{-\frac {5 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {5 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{2 c^5 e^6}+\frac {15 d^2 2^{-2 (p+1)} e^{-\frac {4 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {4 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^4 e^6}-\frac {5 d^3 3^{-p} e^{-\frac {3 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^3 e^6}+\frac {15 d^4 2^{-p-2} e^{-\frac {2 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {2 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^2 e^6}-\frac {3 d^5 e^{-\frac {a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )}{2 c e^6} \]

[Out]

2^(-2-p)*GAMMA(1+p,-6*(a+b*ln(c*(d+e*x^(2/3))))/b)*(a+b*ln(c*(d+e*x^(2/3))))^p/(3^p)/c^6/e^6/exp(6*a/b)/(((-a-
b*ln(c*(d+e*x^(2/3))))/b)^p)-3/2*d*GAMMA(1+p,-5*(a+b*ln(c*(d+e*x^(2/3))))/b)*(a+b*ln(c*(d+e*x^(2/3))))^p/(5^p)
/c^5/e^6/exp(5*a/b)/(((-a-b*ln(c*(d+e*x^(2/3))))/b)^p)+15*d^2*GAMMA(1+p,-4*(a+b*ln(c*(d+e*x^(2/3))))/b)*(a+b*l
n(c*(d+e*x^(2/3))))^p/(2^(2+2*p))/c^4/e^6/exp(4*a/b)/(((-a-b*ln(c*(d+e*x^(2/3))))/b)^p)-5*d^3*GAMMA(1+p,-3*(a+
b*ln(c*(d+e*x^(2/3))))/b)*(a+b*ln(c*(d+e*x^(2/3))))^p/(3^p)/c^3/e^6/exp(3*a/b)/(((-a-b*ln(c*(d+e*x^(2/3))))/b)
^p)+15*2^(-2-p)*d^4*GAMMA(1+p,-2*(a+b*ln(c*(d+e*x^(2/3))))/b)*(a+b*ln(c*(d+e*x^(2/3))))^p/c^2/e^6/exp(2*a/b)/(
((-a-b*ln(c*(d+e*x^(2/3))))/b)^p)-3/2*d^5*GAMMA(1+p,(-a-b*ln(c*(d+e*x^(2/3))))/b)*(a+b*ln(c*(d+e*x^(2/3))))^p/
c/e^6/exp(a/b)/(((-a-b*ln(c*(d+e*x^(2/3))))/b)^p)

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Rubi [A]  time = 0.87, antiderivative size = 557, normalized size of antiderivative = 1.00, number of steps used = 21, number of rules used = 7, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {2454, 2401, 2389, 2299, 2181, 2390, 2309} \[ \frac {15 d^2 2^{-2 (p+1)} e^{-\frac {4 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \text {Gamma}\left (p+1,-\frac {4 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^4 e^6}-\frac {5 d^3 3^{-p} e^{-\frac {3 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \text {Gamma}\left (p+1,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^3 e^6}+\frac {15 d^4 2^{-p-2} e^{-\frac {2 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \text {Gamma}\left (p+1,-\frac {2 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^2 e^6}+\frac {2^{-p-2} 3^{-p} e^{-\frac {6 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \text {Gamma}\left (p+1,-\frac {6 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^6 e^6}-\frac {3 d 5^{-p} e^{-\frac {5 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \text {Gamma}\left (p+1,-\frac {5 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{2 c^5 e^6}-\frac {3 d^5 e^{-\frac {a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \text {Gamma}\left (p+1,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )}{2 c e^6} \]

Antiderivative was successfully verified.

[In]

Int[x^3*(a + b*Log[c*(d + e*x^(2/3))])^p,x]

[Out]

(2^(-2 - p)*Gamma[1 + p, (-6*(a + b*Log[c*(d + e*x^(2/3))]))/b]*(a + b*Log[c*(d + e*x^(2/3))])^p)/(3^p*c^6*e^6
*E^((6*a)/b)*(-((a + b*Log[c*(d + e*x^(2/3))])/b))^p) - (3*d*Gamma[1 + p, (-5*(a + b*Log[c*(d + e*x^(2/3))]))/
b]*(a + b*Log[c*(d + e*x^(2/3))])^p)/(2*5^p*c^5*e^6*E^((5*a)/b)*(-((a + b*Log[c*(d + e*x^(2/3))])/b))^p) + (15
*d^2*Gamma[1 + p, (-4*(a + b*Log[c*(d + e*x^(2/3))]))/b]*(a + b*Log[c*(d + e*x^(2/3))])^p)/(2^(2*(1 + p))*c^4*
e^6*E^((4*a)/b)*(-((a + b*Log[c*(d + e*x^(2/3))])/b))^p) - (5*d^3*Gamma[1 + p, (-3*(a + b*Log[c*(d + e*x^(2/3)
)]))/b]*(a + b*Log[c*(d + e*x^(2/3))])^p)/(3^p*c^3*e^6*E^((3*a)/b)*(-((a + b*Log[c*(d + e*x^(2/3))])/b))^p) +
(15*2^(-2 - p)*d^4*Gamma[1 + p, (-2*(a + b*Log[c*(d + e*x^(2/3))]))/b]*(a + b*Log[c*(d + e*x^(2/3))])^p)/(c^2*
e^6*E^((2*a)/b)*(-((a + b*Log[c*(d + e*x^(2/3))])/b))^p) - (3*d^5*Gamma[1 + p, -((a + b*Log[c*(d + e*x^(2/3))]
)/b)]*(a + b*Log[c*(d + e*x^(2/3))])^p)/(2*c*e^6*E^(a/b)*(-((a + b*Log[c*(d + e*x^(2/3))])/b))^p)

Rule 2181

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> -Simp[(F^(g*(e - (c*f)/d))*(c +
d*x)^FracPart[m]*Gamma[m + 1, (-((f*g*Log[F])/d))*(c + d*x)])/(d*(-((f*g*Log[F])/d))^(IntPart[m] + 1)*(-((f*g*
Log[F]*(c + d*x))/d))^FracPart[m]), x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rule 2299

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_), x_Symbol] :> Dist[1/(n*c^(1/n)), Subst[Int[E^(x/n)*(a + b*x)^p
, x], x, Log[c*x^n]], x] /; FreeQ[{a, b, c, p}, x] && IntegerQ[1/n]

Rule 2309

Int[((a_.) + Log[(c_.)*(x_)]*(b_.))^(p_)*(x_)^(m_.), x_Symbol] :> Dist[1/c^(m + 1), Subst[Int[E^((m + 1)*x)*(a
+ b*x)^p, x], x, Log[c*x]], x] /; FreeQ[{a, b, c, p}, x] && IntegerQ[m]

Rule 2389

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.), x_Symbol] :> Dist[1/e, Subst[Int[(a + b*Log[c*
x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, n, p}, x]

Rule 2390

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[((f*x)/d)^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2401

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Int[Exp
andIntegrand[(f + g*x)^q*(a + b*Log[c*(d + e*x)^n])^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && NeQ[
e*f - d*g, 0] && IGtQ[q, 0]

Rule 2454

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.), x_Symbol] :> Dist[1/n, Subst[I
nt[x^(Simplify[(m + 1)/n] - 1)*(a + b*Log[c*(d + e*x)^p])^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p,
q}, x] && IntegerQ[Simplify[(m + 1)/n]] && (GtQ[(m + 1)/n, 0] || IGtQ[q, 0]) &&  !(EqQ[q, 1] && ILtQ[n, 0] &&
IGtQ[m, 0])

Rubi steps

\begin {align*} \int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx &=\frac {3}{2} \operatorname {Subst}\left (\int x^5 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )\\ &=\frac {3}{2} \operatorname {Subst}\left (\int \left (-\frac {d^5 (a+b \log (c (d+e x)))^p}{e^5}+\frac {5 d^4 (d+e x) (a+b \log (c (d+e x)))^p}{e^5}-\frac {10 d^3 (d+e x)^2 (a+b \log (c (d+e x)))^p}{e^5}+\frac {10 d^2 (d+e x)^3 (a+b \log (c (d+e x)))^p}{e^5}-\frac {5 d (d+e x)^4 (a+b \log (c (d+e x)))^p}{e^5}+\frac {(d+e x)^5 (a+b \log (c (d+e x)))^p}{e^5}\right ) \, dx,x,x^{2/3}\right )\\ &=\frac {3 \operatorname {Subst}\left (\int (d+e x)^5 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{2 e^5}-\frac {(15 d) \operatorname {Subst}\left (\int (d+e x)^4 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{2 e^5}+\frac {\left (15 d^2\right ) \operatorname {Subst}\left (\int (d+e x)^3 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{e^5}-\frac {\left (15 d^3\right ) \operatorname {Subst}\left (\int (d+e x)^2 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{e^5}+\frac {\left (15 d^4\right ) \operatorname {Subst}\left (\int (d+e x) (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{2 e^5}-\frac {\left (3 d^5\right ) \operatorname {Subst}\left (\int (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{2 e^5}\\ &=\frac {3 \operatorname {Subst}\left (\int x^5 (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{2 e^6}-\frac {(15 d) \operatorname {Subst}\left (\int x^4 (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{2 e^6}+\frac {\left (15 d^2\right ) \operatorname {Subst}\left (\int x^3 (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{e^6}-\frac {\left (15 d^3\right ) \operatorname {Subst}\left (\int x^2 (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{e^6}+\frac {\left (15 d^4\right ) \operatorname {Subst}\left (\int x (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{2 e^6}-\frac {\left (3 d^5\right ) \operatorname {Subst}\left (\int (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{2 e^6}\\ &=\frac {3 \operatorname {Subst}\left (\int e^{6 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{2 c^6 e^6}-\frac {(15 d) \operatorname {Subst}\left (\int e^{5 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{2 c^5 e^6}+\frac {\left (15 d^2\right ) \operatorname {Subst}\left (\int e^{4 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{c^4 e^6}-\frac {\left (15 d^3\right ) \operatorname {Subst}\left (\int e^{3 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{c^3 e^6}+\frac {\left (15 d^4\right ) \operatorname {Subst}\left (\int e^{2 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{2 c^2 e^6}-\frac {\left (3 d^5\right ) \operatorname {Subst}\left (\int e^x (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{2 c e^6}\\ &=\frac {2^{-2-p} 3^{-p} e^{-\frac {6 a}{b}} \Gamma \left (1+p,-\frac {6 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^6 e^6}-\frac {3\ 5^{-p} d e^{-\frac {5 a}{b}} \Gamma \left (1+p,-\frac {5 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{2 c^5 e^6}+\frac {15\ 4^{-1-p} d^2 e^{-\frac {4 a}{b}} \Gamma \left (1+p,-\frac {4 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^4 e^6}-\frac {5\ 3^{-p} d^3 e^{-\frac {3 a}{b}} \Gamma \left (1+p,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^3 e^6}+\frac {15\ 2^{-2-p} d^4 e^{-\frac {2 a}{b}} \Gamma \left (1+p,-\frac {2 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^2 e^6}-\frac {3 d^5 e^{-\frac {a}{b}} \Gamma \left (1+p,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{2 c e^6}\\ \end {align*}

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Mathematica [A]  time = 0.94, size = 325, normalized size = 0.58 \[ \frac {4^{-p-1} 15^{-p} e^{-\frac {6 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \left (10^p \Gamma \left (p+1,-\frac {6 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )-c d e^{a/b} \left (2^{2 p+1} 3^{p+1} \Gamma \left (p+1,-\frac {5 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )+c d 5^p e^{a/b} \left (c d 2^p e^{a/b} \left (5\ 2^{p+2} \Gamma \left (p+1,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )+c d 3^{p+1} e^{a/b} \left (c d 2^{p+1} e^{a/b} \Gamma \left (p+1,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )-5 \Gamma \left (p+1,-\frac {2 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )\right )\right )-5\ 3^{p+1} \Gamma \left (p+1,-\frac {4 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )\right )\right )\right )}{c^6 e^6} \]

Antiderivative was successfully verified.

[In]

Integrate[x^3*(a + b*Log[c*(d + e*x^(2/3))])^p,x]

[Out]

(4^(-1 - p)*(10^p*Gamma[1 + p, (-6*(a + b*Log[c*(d + e*x^(2/3))]))/b] - c*d*E^(a/b)*(2^(1 + 2*p)*3^(1 + p)*Gam
ma[1 + p, (-5*(a + b*Log[c*(d + e*x^(2/3))]))/b] + 5^p*c*d*E^(a/b)*(-5*3^(1 + p)*Gamma[1 + p, (-4*(a + b*Log[c
*(d + e*x^(2/3))]))/b] + 2^p*c*d*E^(a/b)*(5*2^(2 + p)*Gamma[1 + p, (-3*(a + b*Log[c*(d + e*x^(2/3))]))/b] + 3^
(1 + p)*c*d*E^(a/b)*(-5*Gamma[1 + p, (-2*(a + b*Log[c*(d + e*x^(2/3))]))/b] + 2^(1 + p)*c*d*E^(a/b)*Gamma[1 +
p, -((a + b*Log[c*(d + e*x^(2/3))])/b)])))))*(a + b*Log[c*(d + e*x^(2/3))])^p)/(15^p*c^6*e^6*E^((6*a)/b)*(-((a
+ b*Log[c*(d + e*x^(2/3))])/b))^p)

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fricas [F]  time = 0.74, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (b \log \left (c e x^{\frac {2}{3}} + c d\right ) + a\right )}^{p} x^{3}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*(d+e*x^(2/3))))^p,x, algorithm="fricas")

[Out]

integral((b*log(c*e*x^(2/3) + c*d) + a)^p*x^3, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \log \left ({\left (e x^{\frac {2}{3}} + d\right )} c\right ) + a\right )}^{p} x^{3}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*(d+e*x^(2/3))))^p,x, algorithm="giac")

[Out]

integrate((b*log((e*x^(2/3) + d)*c) + a)^p*x^3, x)

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maple [F]  time = 0.18, size = 0, normalized size = 0.00 \[ \int x^{3} \left (b \ln \left (\left (e \,x^{\frac {2}{3}}+d \right ) c \right )+a \right )^{p}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a+b*ln(c*(e*x^(2/3)+d)))^p,x)

[Out]

int(x^3*(a+b*ln(c*(e*x^(2/3)+d)))^p,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \log \left ({\left (e x^{\frac {2}{3}} + d\right )} c\right ) + a\right )}^{p} x^{3}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*(d+e*x^(2/3))))^p,x, algorithm="maxima")

[Out]

integrate((b*log((e*x^(2/3) + d)*c) + a)^p*x^3, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int x^3\,{\left (a+b\,\ln \left (c\,\left (d+e\,x^{2/3}\right )\right )\right )}^p \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a + b*log(c*(d + e*x^(2/3))))^p,x)

[Out]

int(x^3*(a + b*log(c*(d + e*x^(2/3))))^p, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(a+b*ln(c*(d+e*x**(2/3))))**p,x)

[Out]

Timed out

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